The diagram above (Fig.1.10) represents the velocity - time graph of a body in motion. The total distance travelled by the body is 195m. Calculate the acceleration of the body in section OP of the graph.

John Perolski
August 22, 2023

Physics Jamb, Waec, Neco Past Questions & Answers on Speed, Velocity and Acceleration



Questions 22: The diagram above (Fig.1.10) represents the velocity - time graph of a body in motion. The total distance travelled by the body is 195m. Calculate the acceleration of the body in section OP of the graph. 

WAEC 1994 Ans: 2.5m/s2

Solutions 

Total distance S = 195m

Total time taken t = 21s

Therefore final velocity or change in  velocity  v= distance/time 

v = 195/21

v = 9.29m/s

Hence acceleration in section OP

Time t = 6s

Acceleration a = ?

Initial velocity u= 0m/s

Final velocity v = 9.29 

Using v = u +at

9.29 = 0 +a x 6

9.29 = 0 +6a

9.29-0 = 6a

a = 9.29/6

a = 1.55m/s² Answer