The figure below (Fig. 1.13) shows the velocity - time graph of a car which starts from rest and is accelerated uniformly at the rate of 3m/s² for 5 seconds. It attains a velocity which is maintained for 1 minute. The car is then brought to rest by a uniform retardation after another 3 seconds. Calculate the total distance covered.

Physics Jamb, Waec, Neco Past Questions & Answers on Speed, Velocity and Acceleration

QUESTIONS 25. The figure below (Fig. 1.13) shows the velocity - time graph of a car which starts from rest and is accelerated uniformly at the rate of 3m/s² for 5 seconds. It attains a velocity which is maintained for 1 minute. The car is then brought to rest by a uniform retardation after another 3 seconds. Calculate the total distance covered.

A. 900meters B.1920meters C.1020meters D.960meters E.860meters

JAMB 1979 Ans: 960m

SOLUTIONS:

Total Distance S, = area of shape

Area = (½ x b x h) + (l x w) + (½ X b x h)

s = 1/2(15)(5) + 60×15 + 1/2(15)(3)

= 960m.

Or

To find v

a=(v-u)/t, u=0,

v= 5×3= 15m/s

Total Distance D = area of shape

Distance s, = 1/2(15)(5) + 60×15 + 1/2(15)(3)

Distance S, = 960m. Answer.