A force, 10N drags a mass 10kg on a horizontal table with an acceleration of 0.2m/s². If the acceleration due to gravity is 10m/s², the coefficient of friction between the moving mass and the table is?
Physics Jamb, Waec, Neco Past Questions & Answers on FRICTIONAL FORCE
QUESTIONS 8: A force, 10N drags a mass 10kg on a horizontal table with an acceleration of 0.2m/s². If the acceleration due to gravity is 10m/s², the coefficient of friction between the moving mass and the table is?
A. 0.02
B. 0.08
C. 0.20
D. 0.80
Ans: 0.08 JAMB 1988
SOLUTIONS
μmg = ma
F = μR
R = mg
F = μmg
R = F - P
μmg = F - ma
μ x 10 x 10 = 10 - (10 x 0.2)
100 μ =10 - 2
dividing both sides by 100
μ = 8 / 100
μ = 0.08
Or
F -Fr = umg
where F is applied force
fr is d frictional force
Fr = ma
F - ma = umg
10 - 10 × 0.2 = 10 × 10×u
8 = 100μ
μ = 0.08
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